substitute x = a - 2.5 2.5 is avg of 1,2,3,4 then, substitute a^2 = u + 1.25 1.25 is also avg Ez..
Wow! That makes a mountain out of a molehill! I would hope that someone entering Harvard would say, the product is of 4 consecutive numbers. 120 = 5! so the four numbers are 2, 3, 4, 5. Therefore x = 1. I suspect that going into that level of detail would not impress the interviewer. PS: I have my own interview failure question from 50 years ago at Cambridge (UK) involving a cube of resistors and finding the overall resistance across the corners. Still haven't worked that one out yet.
After some meditation you see that the equation is equivalent to (x^2 +5x +5)^2 = 121. The rest is easy.
I could see "X=1" in just a glance. Does Harvard specify that it wants ALL the possible solutions, or just a solution that works?
Sir, you are great😃. Go ahead❤
Muchas vueltas. Sí por simple inspección o por descomposición de factores. X=1. Entonces. (1+1) (1+2)(1+3)(1+4)= 120.
x^2 + 5x + 5 = u => (u - 1)(u + 1) = 120
Simple method, LHS मे x का मान 1रखने पर = 120 So LHS=RHS.
120=5!=(4+1)(3+1)(2+1)(1+1) So x=1 ans.
In a blink x is solved x=1
How are so many people over explaining over thinking and getting the wrong number for x 😂 I literally glanced at it and could see x=1
2×3×4×5=120. X=1 is a solution
(x+1)(x+2)(x+3)(x+4) = 120. * 120 = 10 x 12 = 2x5 x 3x4 = 2 x 3 x 4 x 5. = (1+1)(1+2)(1+3)(1+4) ** x = 1./.
Если бы в Гарварде давали такие задания,туда поступил бы любой желающий.Не нужно врать!
Bro geometry please 🙏🙏
why repeat the problem? we can all see it
Where is the practical use?
120を素因数分解するだけだよ! 120=2exp3×3×5=2×3×4×5
x=1 e x=-6
@yurenchu