@RaghavMukhija
Just Amazing, as usual ❤ 2x²+y²+2xy-2y+2=0 ⇒ 2x²+4+8x-4+2=0 ⇒ 2x²+8x+2=0 ⇒ x=[-b±√(b²-4ac) ]/ 2a ⇒ x=[-8±√(8²-4(2)(2)) ]/ 2(2) ⇒ x=[-8±√(64-16) ]/4 ⇒ x=[-8±√48 ]/4 ⇒ x=[-8±4√3 ]/4 ⇒ x=(-8+4√3)/4 and (-8-4√3)/4 ⇒x= (-2+4√3) and (-2-√3)
@saikatchakraborty4012
Wow just splendid
@something-31
Looks like pretty nice feature. Hoping for it use asap Btw I guess i have other solution by observing the quadratic its pretty clear that we need only one x^2 and 2y^2 so substitute y'=2y and complete the whole square to get (x+y')^2 + (y'-1)^2=0 Therefore, x+y'=0 and y'=1 So, x=-1 and y=2y'=2 is only possible real solution
@arun-cr8sn
Sir, please make a detailed video for ISI MSTAT exam, and how to prepare for this exam by self-study, from where we can complete the theory part in detailed and from where to practice question especially subjective questions and which book we should follow for ISI MSTAT exam for both objective questions, and especially subjective questions, and how to strengthen our concepts for this exam. And also please provide information regarding different courses of Cheenta Academy for ISI MSTAT, like crash course or mock test, with their respective prices, and what will be provided in these courses, and other useful information regarding this exam.
@phobiaticgamerz
Sir my geometry is not improve what can i do
@SamarthaShetty-vr5of
Supr sir❤
@venkateshstudent197
Can anyone send the link to access this software
@coderpro5141
will it be for everybody,
@tamojitmondal1243
will this tool be available for everyone ?
@ImOwnef
2x²+4+8x-4+2=0 =>2x²+8x+2=0 =>x=-8±√(64-16) /4 =>x=-8±4√3/4 =>x=-8+4√3/4, x=-8-4√3/4 =>x=-2+4√3, x=-2-√3 👅👅
@madhurpopli1790